48x^2+48xy^2+12y^4=

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Solution for 48x^2+48xy^2+12y^4= equation:


Simplifying
48x2 + 48xy2 + 12y4 = 0

Reorder the terms:
48xy2 + 48x2 + 12y4 = 0

Solving
48xy2 + 48x2 + 12y4 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '12'.
12(4xy2 + 4x2 + y4) = 0

Factor a trinomial.
12((2x + y2)(2x + y2)) = 0

Ignore the factor 12.

Subproblem 1

Set the factor '(2x + y2)' equal to zero and attempt to solve: Simplifying 2x + y2 = 0 Solving 2x + y2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-1y2' to each side of the equation. 2x + y2 + -1y2 = 0 + -1y2 Combine like terms: y2 + -1y2 = 0 2x + 0 = 0 + -1y2 2x = 0 + -1y2 Remove the zero: 2x = -1y2 Divide each side by '2'. x = -0.5y2 Simplifying x = -0.5y2

Subproblem 2

Set the factor '(2x + y2)' equal to zero and attempt to solve: Simplifying 2x + y2 = 0 Solving 2x + y2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-1y2' to each side of the equation. 2x + y2 + -1y2 = 0 + -1y2 Combine like terms: y2 + -1y2 = 0 2x + 0 = 0 + -1y2 2x = 0 + -1y2 Remove the zero: 2x = -1y2 Divide each side by '2'. x = -0.5y2 Simplifying x = -0.5y2

Solution

x = {-0.5y2, -0.5y2}

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